11413311101 has 2 divisors, whose sum is σ = 11413311102. Its totient is φ = 11413311100.

The previous prime is 11413311083. The next prime is 11413311103. The reversal of 11413311101 is 10111331411.

11413311101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7024116100 + 4389195001 = 83810^2 + 66251^2 .

It is a cyclic number.

It is not a de Polignac number, because 11413311101 - 2⁶ = 11413311037 is a prime.

Together with 11413311103, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11413311101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11413311103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706655550 + 5706655551.

It is an arithmetic number, because the mean of its divisors is an integer number (5706655551).

Almost surely, 2^11413311101 is an apocalyptic number.

It is an amenable number.

11413311101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413311101 is an equidigital number, since it uses as much as digits as its factorization.

11413311101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 11413311101 its reverse (10111331411), we get a palindrome (21524642512).

The spelling of 11413311101 in words is "eleven billion, four hundred thirteen million, three hundred eleven thousand, one hundred one".