Base | Representation |
---|---|
bin | 110101001001011011… |
… | …1100110110111010101 |
3 | 101220121010202022100012 |
4 | 1222102313212313111 |
5 | 3332221044402331 |
6 | 124233154330005 |
7 | 11150220124136 |
oct | 1522267466725 |
9 | 356533668305 |
10 | 114133200341 |
11 | 44449241766 |
12 | 1a152b89905 |
13 | a9bb8b7994 |
14 | 574a0cbc8d |
15 | 2e7edce82b |
hex | 1a92de6dd5 |
114133200341 has 2 divisors, whose sum is σ = 114133200342. Its totient is φ = 114133200340.
The previous prime is 114133200319. The next prime is 114133200343. The reversal of 114133200341 is 143002331411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66025358116 + 48107842225 = 256954^2 + 219335^2 .
It is a cyclic number.
It is not a de Polignac number, because 114133200341 - 222 = 114129006037 is a prime.
Together with 114133200343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114133200343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066600170 + 57066600171.
It is an arithmetic number, because the mean of its divisors is an integer number (57066600171).
Almost surely, 2114133200341 is an apocalyptic number.
It is an amenable number.
114133200341 is a deficient number, since it is larger than the sum of its proper divisors (1).
114133200341 is an equidigital number, since it uses as much as digits as its factorization.
114133200341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 114133200341 its reverse (143002331411), we get a palindrome (257135531752).
The spelling of 114133200341 in words is "one hundred fourteen billion, one hundred thirty-three million, two hundred thousand, three hundred forty-one".
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