1141344403301 has 2 divisors, whose sum is σ = 1141344403302. Its totient is φ = 1141344403300.

The previous prime is 1141344403279. The next prime is 1141344403313. The reversal of 1141344403301 is 1033044431411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1141320442276 + 23961025 = 1068326^2 + 4895^2 .

It is an emirp because it is prime and its reverse (1033044431411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1141344403301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141344403321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570672201650 + 570672201651.

It is an arithmetic number, because the mean of its divisors is an integer number (570672201651).

Almost surely, 2^{1141344403301} is an apocalyptic number.

It is an amenable number.

1141344403301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141344403301 is an equidigital number, since it uses as much as digits as its factorization.

1141344403301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1141344403301 its reverse (1033044431411), we get a palindrome (2174388834712).

The spelling of 1141344403301 in words is "one trillion, one hundred forty-one billion, three hundred forty-four million, four hundred three thousand, three hundred one".