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1141344403313 is a prime number
BaseRepresentation
bin10000100110111101011…
…011010111111101110001
311001010000020212001212112
4100212331123113331301
5122144433131401223
62232154255335105
7145313402233352
oct20467533277561
94033006761775
101141344403313
11400050185154
12165249b21495
138382254164a
143d354433d29
151ea504e9778
hex109bd6d7f71

1141344403313 has 2 divisors, whose sum is σ = 1141344403314. Its totient is φ = 1141344403312.

The previous prime is 1141344403301. The next prime is 1141344403321. The reversal of 1141344403313 is 3133044431411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 914142507664 + 227201895649 = 956108^2 + 476657^2 .

It is an emirp because it is prime and its reverse (3133044431411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141344403313 - 26 = 1141344403249 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1141344403313.

It is not a weakly prime, because it can be changed into another prime (1141344409313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570672201656 + 570672201657.

It is an arithmetic number, because the mean of its divisors is an integer number (570672201657).

Almost surely, 21141344403313 is an apocalyptic number.

It is an amenable number.

1141344403313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141344403313 is an equidigital number, since it uses as much as digits as its factorization.

1141344403313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 1141344403313 its reverse (3133044431411), we get a palindrome (4274388834724).

The spelling of 1141344403313 in words is "one trillion, one hundred forty-one billion, three hundred forty-four million, four hundred three thousand, three hundred thirteen".