Base | Representation |
---|---|
bin | 10000100110111101011… |
… | …011011001011011100001 |
3 | 11001010000020212101002202 |
4 | 100212331123121123201 |
5 | 122144433132044223 |
6 | 2232154255422545 |
7 | 145313402260013 |
oct | 20467533313341 |
9 | 4033006771082 |
10 | 1141344409313 |
11 | 400050189709 |
12 | 165249b24a55 |
13 | 838225442b4 |
14 | 3d3544361b3 |
15 | 1ea504eb428 |
hex | 109bd6d96e1 |
1141344409313 has 2 divisors, whose sum is σ = 1141344409314. Its totient is φ = 1141344409312.
The previous prime is 1141344409267. The next prime is 1141344409399. The reversal of 1141344409313 is 3139044431411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 605444278609 + 535900130704 = 778103^2 + 732052^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141344409313 - 218 = 1141344147169 is a prime.
It is a super-2 number, since 2×11413444093132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1141344409813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570672204656 + 570672204657.
It is an arithmetic number, because the mean of its divisors is an integer number (570672204657).
Almost surely, 21141344409313 is an apocalyptic number.
It is an amenable number.
1141344409313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141344409313 is an equidigital number, since it uses as much as digits as its factorization.
1141344409313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 1141344409313 in words is "one trillion, one hundred forty-one billion, three hundred forty-four million, four hundred nine thousand, three hundred thirteen".
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