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114135131081 is a prime number
BaseRepresentation
bin110101001001011111…
…0111110001111001001
3101220121021101101211002
41222102332332033021
53332222043143311
6124233303544345
711150242415126
oct1522276761711
9356537341732
10114135131081
114444a340314
121a15375b0b5
13a9bc11272a
14574a47174d
152e8016193b
hex1a92fbe3c9

114135131081 has 2 divisors, whose sum is σ = 114135131082. Its totient is φ = 114135131080.

The previous prime is 114135130951. The next prime is 114135131083. The reversal of 114135131081 is 180131531411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109815355456 + 4319775625 = 331384^2 + 65725^2 .

It is a cyclic number.

It is not a de Polignac number, because 114135131081 - 226 = 114068022217 is a prime.

It is a super-2 number, since 2×1141351310812 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 114135131083, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (114135131083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067565540 + 57067565541.

It is an arithmetic number, because the mean of its divisors is an integer number (57067565541).

Almost surely, 2114135131081 is an apocalyptic number.

It is an amenable number.

114135131081 is a deficient number, since it is larger than the sum of its proper divisors (1).

114135131081 is an equidigital number, since it uses as much as digits as its factorization.

114135131081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 114135131081 its reverse (180131531411), we get a palindrome (294266662492).

The spelling of 114135131081 in words is "one hundred fourteen billion, one hundred thirty-five million, one hundred thirty-one thousand, eighty-one".