Base | Representation |
---|---|
bin | 11001111100111101010000… |
… | …100110000100010101010001 |
3 | 112222010200120101020202100222 |
4 | 121330331100212010111101 |
5 | 104430032420130011242 |
6 | 1042431124115322425 |
7 | 33020231165343104 |
oct | 3174752046042521 |
9 | 488120511222328 |
10 | 114140108047697 |
11 | 33406603403816 |
12 | 1097514b2b0415 |
13 | 4b8c49b15c714 |
14 | 20285a6d9673b |
15 | d2e0a5b335d2 |
hex | 67cf50984551 |
114140108047697 has 2 divisors, whose sum is σ = 114140108047698. Its totient is φ = 114140108047696.
The previous prime is 114140108047657. The next prime is 114140108047709. The reversal of 114140108047697 is 796740801041411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106608288866641 + 7531819181056 = 10325129^2 + 2744416^2 .
It is a cyclic number.
It is not a de Polignac number, because 114140108047697 - 216 = 114140107982161 is a prime.
It is not a weakly prime, because it can be changed into another prime (114140108047657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57070054023848 + 57070054023849.
It is an arithmetic number, because the mean of its divisors is an integer number (57070054023849).
Almost surely, 2114140108047697 is an apocalyptic number.
It is an amenable number.
114140108047697 is a deficient number, since it is larger than the sum of its proper divisors (1).
114140108047697 is an equidigital number, since it uses as much as digits as its factorization.
114140108047697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1354752, while the sum is 53.
The spelling of 114140108047697 in words is "one hundred fourteen trillion, one hundred forty billion, one hundred eight million, forty-seven thousand, six hundred ninety-seven".
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