Base | Representation |
---|---|
bin | 11001111100111110011101… |
… | …111111000001100000010111 |
3 | 112222010210220212101200101121 |
4 | 121330332131333001200113 |
5 | 104430043100021412401 |
6 | 1042431501020304411 |
7 | 33020305312426621 |
oct | 3174763577014027 |
9 | 488123825350347 |
10 | 114141406435351 |
11 | 3340710a2aa669 |
12 | 109754520a2107 |
13 | 4b8c647151839 |
14 | 202868b5b7c11 |
15 | d2e12eb05ca1 |
hex | 67cf9dfc1817 |
114141406435351 has 2 divisors, whose sum is σ = 114141406435352. Its totient is φ = 114141406435350.
The previous prime is 114141406435349. The next prime is 114141406435439. The reversal of 114141406435351 is 153534604141411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114141406435351 - 21 = 114141406435349 is a prime.
Together with 114141406435349, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 114141406435298 and 114141406435307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114141406435751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57070703217675 + 57070703217676.
It is an arithmetic number, because the mean of its divisors is an integer number (57070703217676).
Almost surely, 2114141406435351 is an apocalyptic number.
114141406435351 is a deficient number, since it is larger than the sum of its proper divisors (1).
114141406435351 is an equidigital number, since it uses as much as digits as its factorization.
114141406435351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 43.
The spelling of 114141406435351 in words is "one hundred fourteen trillion, one hundred forty-one billion, four hundred six million, four hundred thirty-five thousand, three hundred fifty-one".
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