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114147350413 is a prime number
BaseRepresentation
bin110101001001110110…
…1100101011110001101
3101220122010101012120221
41222103231211132031
53332233210203123
6124234421511341
711150451320035
oct1522355453615
9356563335527
10114147350413
1144456226938
121a157872551
13a9c18004c5
14574bd328c5
152e8127725d
hex1a93b6578d

114147350413 has 2 divisors, whose sum is σ = 114147350414. Its totient is φ = 114147350412.

The previous prime is 114147350381. The next prime is 114147350419. The reversal of 114147350413 is 314053741411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86716703529 + 27430646884 = 294477^2 + 165622^2 .

It is a cyclic number.

It is not a de Polignac number, because 114147350413 - 25 = 114147350381 is a prime.

It is a super-2 number, since 2×1141473504132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114147350419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57073675206 + 57073675207.

It is an arithmetic number, because the mean of its divisors is an integer number (57073675207).

Almost surely, 2114147350413 is an apocalyptic number.

It is an amenable number.

114147350413 is a deficient number, since it is larger than the sum of its proper divisors (1).

114147350413 is an equidigital number, since it uses as much as digits as its factorization.

114147350413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 114147350413 in words is "one hundred fourteen billion, one hundred forty-seven million, three hundred fifty thousand, four hundred thirteen".