Base | Representation |
---|---|
bin | 110101001010000000… |
… | …1100111011011010101 |
3 | 101220122111020222110021 |
4 | 1222110001213123111 |
5 | 3332241031220201 |
6 | 124235130225141 |
7 | 11150544046534 |
oct | 1522401473325 |
9 | 356574228407 |
10 | 114152601301 |
11 | 44459192a12 |
12 | 1a1595851b1 |
13 | a9c291b53b |
14 | 574c8dc31b |
15 | 2e81962ea1 |
hex | 1a940676d5 |
114152601301 has 2 divisors, whose sum is σ = 114152601302. Its totient is φ = 114152601300.
The previous prime is 114152601151. The next prime is 114152601361. The reversal of 114152601301 is 103106251411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103870844100 + 10281757201 = 322290^2 + 101399^2 .
It is an emirp because it is prime and its reverse (103106251411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114152601301 - 29 = 114152600789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114152601361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57076300650 + 57076300651.
It is an arithmetic number, because the mean of its divisors is an integer number (57076300651).
Almost surely, 2114152601301 is an apocalyptic number.
It is an amenable number.
114152601301 is a deficient number, since it is larger than the sum of its proper divisors (1).
114152601301 is an equidigital number, since it uses as much as digits as its factorization.
114152601301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 114152601301 its reverse (103106251411), we get a palindrome (217258852712).
The spelling of 114152601301 in words is "one hundred fourteen billion, one hundred fifty-two million, six hundred one thousand, three hundred one".
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