Base | Representation |
---|---|
bin | 110101001010000001… |
… | …1111101010111000111 |
3 | 101220122112102011212211 |
4 | 1222110003331113013 |
5 | 3332241210343211 |
6 | 124235151324251 |
7 | 11150552215153 |
oct | 1522403752707 |
9 | 356575364784 |
10 | 114153215431 |
11 | 44459572362 |
12 | 1a159820687 |
13 | a9c2aa4c28 |
14 | 574ca1c063 |
15 | 2e81a34e21 |
hex | 1a940fd5c7 |
114153215431 has 2 divisors, whose sum is σ = 114153215432. Its totient is φ = 114153215430.
The previous prime is 114153215419. The next prime is 114153215483. The reversal of 114153215431 is 134512351411.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (134512351411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114153215431 - 223 = 114144826823 is a prime.
It is a super-2 number, since 2×1141532154312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114153215393 and 114153215402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114153215131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57076607715 + 57076607716.
It is an arithmetic number, because the mean of its divisors is an integer number (57076607716).
Almost surely, 2114153215431 is an apocalyptic number.
114153215431 is a deficient number, since it is larger than the sum of its proper divisors (1).
114153215431 is an equidigital number, since it uses as much as digits as its factorization.
114153215431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 31.
Adding to 114153215431 its reverse (134512351411), we get a palindrome (248665566842).
The spelling of 114153215431 in words is "one hundred fourteen billion, one hundred fifty-three million, two hundred fifteen thousand, four hundred thirty-one".
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