114159433 has 2 divisors, whose sum is σ = 114159434. Its totient is φ = 114159432.

The previous prime is 114159431. The next prime is 114159439. The reversal of 114159433 is 334951411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113784889 + 374544 = 10667^2 + 612^2 .

It is a cyclic number.

It is not a de Polignac number, because 114159433 - 2¹ = 114159431 is a prime.

It is a super-3 number, since 3×114159433³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 114159431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 114159395 and 114159404.

It is not a weakly prime, because it can be changed into another prime (114159431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57079716 + 57079717.

It is an arithmetic number, because the mean of its divisors is an integer number (57079717).

Almost surely, 2^114159433 is an apocalyptic number.

It is an amenable number.

114159433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114159433 is an equidigital number, since it uses as much as digits as its factorization.

114159433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 31.

The square root of 114159433 is about 10684.5417777273. The cubic root of 114159433 is about 485.1066942085.

The spelling of 114159433 in words is "one hundred fourteen million, one hundred fifty-nine thousand, four hundred thirty-three".