Base | Representation |
---|---|
bin | 10000100111101010101… |
… | …110001101000110111101 |
3 | 11001011222012202112202221 |
4 | 100213222232031012331 |
5 | 122203012201024201 |
6 | 2232401523045341 |
7 | 145341260331316 |
oct | 20475256150675 |
9 | 4034865675687 |
10 | 1142104314301 |
11 | 400400124565 |
12 | 165420510851 |
13 | 83913ac9312 |
14 | 3d3c732560d |
15 | 1ea970a34a1 |
hex | 109eab8d1bd |
1142104314301 has 2 divisors, whose sum is σ = 1142104314302. Its totient is φ = 1142104314300.
The previous prime is 1142104314293. The next prime is 1142104314317. The reversal of 1142104314301 is 1034134012411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1131881082201 + 10223232100 = 1063899^2 + 101110^2 .
It is a cyclic number.
It is not a de Polignac number, because 1142104314301 - 23 = 1142104314293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1142104315301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571052157150 + 571052157151.
It is an arithmetic number, because the mean of its divisors is an integer number (571052157151).
Almost surely, 21142104314301 is an apocalyptic number.
It is an amenable number.
1142104314301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142104314301 is an equidigital number, since it uses as much as digits as its factorization.
1142104314301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1142104314301 its reverse (1034134012411), we get a palindrome (2176238326712).
The spelling of 1142104314301 in words is "one trillion, one hundred forty-two billion, one hundred four million, three hundred fourteen thousand, three hundred one".
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