Base | Representation |
---|---|
bin | 11001111110001001100100… |
… | …011000000111011000111111 |
3 | 112222102112001122210022020021 |
4 | 121332021210120013120333 |
5 | 104432403221321010101 |
6 | 1042532514402033011 |
7 | 33026161511166355 |
oct | 3176114430073077 |
9 | 488375048708207 |
10 | 114222044313151 |
11 | 3343832a285785 |
12 | 10988bb7648767 |
13 | 4b97128484b28 |
14 | 202c53ad597d5 |
15 | d3129e0c55a1 |
hex | 67e26460763f |
114222044313151 has 2 divisors, whose sum is σ = 114222044313152. Its totient is φ = 114222044313150.
The previous prime is 114222044313037. The next prime is 114222044313173. The reversal of 114222044313151 is 151313440222411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114222044313151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114222044383151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111022156575 + 57111022156576.
It is an arithmetic number, because the mean of its divisors is an integer number (57111022156576).
Almost surely, 2114222044313151 is an apocalyptic number.
114222044313151 is a deficient number, since it is larger than the sum of its proper divisors (1).
114222044313151 is an equidigital number, since it uses as much as digits as its factorization.
114222044313151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 114222044313151 its reverse (151313440222411), we get a palindrome (265535484535562).
The spelling of 114222044313151 in words is "one hundred fourteen trillion, two hundred twenty-two billion, forty-four million, three hundred thirteen thousand, one hundred fifty-one".
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