1142224413331 has 2 divisors, whose sum is σ = 1142224413332. Its totient is φ = 1142224413330.

The previous prime is 1142224413329. The next prime is 1142224413347. The reversal of 1142224413331 is 1333144222411.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1333144222411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1142224413331 - 2¹ = 1142224413329 is a prime.

It is a super-2 number, since 2×1142224413331² (a number of 25 digits) contains 22 as substring.

Together with 1142224413329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1142224413293 and 1142224413302.

It is not a weakly prime, because it can be changed into another prime (1142224413731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571112206665 + 571112206666.

It is an arithmetic number, because the mean of its divisors is an integer number (571112206666).

Almost surely, 2^{1142224413331} is an apocalyptic number.

1142224413331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142224413331 is an equidigital number, since it uses as much as digits as its factorization.

1142224413331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 31.

Adding to 1142224413331 its reverse (1333144222411), we get a palindrome (2475368635742).

The spelling of 1142224413331 in words is "one trillion, one hundred forty-two billion, two hundred twenty-four million, four hundred thirteen thousand, three hundred thirty-one".