Base | Representation |
---|---|
bin | 11001111110010001000001… |
… | …000110000001111011111011 |
3 | 112222110021201001102100102212 |
4 | 121332101001012001323323 |
5 | 104433021111312214001 |
6 | 1042540320150445335 |
7 | 33026563636041566 |
oct | 3176210106017373 |
9 | 488407631370385 |
10 | 114230042304251 |
11 | 33440763a00885 |
12 | 1098a66a06384b |
13 | 4b97b01473743 |
14 | 202ca9925d4dd |
15 | d315bb3257bb |
hex | 67e441181efb |
114230042304251 has 2 divisors, whose sum is σ = 114230042304252. Its totient is φ = 114230042304250.
The previous prime is 114230042304151. The next prime is 114230042304253. The reversal of 114230042304251 is 152403240032411.
It is a strong prime.
It is an emirp because it is prime and its reverse (152403240032411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114230042304251 is a prime.
Together with 114230042304253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (114230042304253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57115021152125 + 57115021152126.
It is an arithmetic number, because the mean of its divisors is an integer number (57115021152126).
Almost surely, 2114230042304251 is an apocalyptic number.
114230042304251 is a deficient number, since it is larger than the sum of its proper divisors (1).
114230042304251 is an equidigital number, since it uses as much as digits as its factorization.
114230042304251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 114230042304251 its reverse (152403240032411), we get a palindrome (266633282336662).
The spelling of 114230042304251 in words is "one hundred fourteen trillion, two hundred thirty billion, forty-two million, three hundred four thousand, two hundred fifty-one".
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