Base | Representation |
---|---|
bin | 11001111110011010011010… |
… | …100001001100010001100100 |
3 | 112222111020202020221222210210 |
4 | 121332122122201030101210 |
5 | 104433202242412000200 |
6 | 1042545105315215420 |
7 | 33030401660413266 |
oct | 3176323241142144 |
9 | 488436666858723 |
10 | 114240132531300 |
11 | 33444a716417a6 |
12 | 109906052a7570 |
13 | 4b98a4ba622a9 |
14 | 202d37538bb36 |
15 | d319ac0a7650 |
hex | 67e69a84c464 |
114240132531300 has 72 divisors (see below), whose sum is σ = 330793216768000. Its totient is φ = 30440216603520.
The previous prime is 114240132531223. The next prime is 114240132531313. The reversal of 114240132531300 is 3135231042411.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 148482775 + ... + 149250174.
Almost surely, 2114240132531300 is an apocalyptic number.
114240132531300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114240132531300 is an abundant number, since it is smaller than the sum of its proper divisors (216553084236700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114240132531300 is a wasteful number, since it uses less digits than its factorization.
114240132531300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 297734245 (or 297734238 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 114240132531300 its reverse (3135231042411), we get a palindrome (117375363573711).
The spelling of 114240132531300 in words is "one hundred fourteen trillion, two hundred forty billion, one hundred thirty-two million, five hundred thirty-one thousand, three hundred".
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