Base | Representation |
---|---|
bin | 110101001100101001… |
… | …0111100011111100101 |
3 | 101220212122122121222121 |
4 | 1222121102330133211 |
5 | 3332431200430432 |
6 | 124252005425541 |
7 | 11152666506514 |
oct | 1523122743745 |
9 | 356778577877 |
10 | 114241030117 |
11 | 444a40a0885 |
12 | 1a18310b2b1 |
13 | aa08040296 |
14 | 575a55a67b |
15 | 2e895ce197 |
hex | 1a994bc7e5 |
114241030117 has 2 divisors, whose sum is σ = 114241030118. Its totient is φ = 114241030116.
The previous prime is 114241030097. The next prime is 114241030147. The reversal of 114241030117 is 711030142411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 85248816676 + 28992213441 = 291974^2 + 170271^2 .
It is a cyclic number.
It is not a de Polignac number, because 114241030117 - 27 = 114241029989 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114241030091 and 114241030100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114241030147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120515058 + 57120515059.
It is an arithmetic number, because the mean of its divisors is an integer number (57120515059).
Almost surely, 2114241030117 is an apocalyptic number.
It is an amenable number.
114241030117 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241030117 is an equidigital number, since it uses as much as digits as its factorization.
114241030117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 114241030117 its reverse (711030142411), we get a palindrome (825271172528).
The spelling of 114241030117 in words is "one hundred fourteen billion, two hundred forty-one million, thirty thousand, one hundred seventeen".
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