Base | Representation |
---|---|
bin | 11001111110011011010100… |
… | …010101011111111001000111 |
3 | 112222111100020212012202200221 |
4 | 121332123110111133321013 |
5 | 104433211234222410310 |
6 | 1042545345450045211 |
7 | 33030435006402055 |
oct | 3176332425377107 |
9 | 488440225182627 |
10 | 114241102544455 |
11 | 3344541a143a67 |
12 | 10990836119807 |
13 | 4b98b74a00483 |
14 | 202d4281311d5 |
15 | d31a17313ada |
hex | 67e6d455fe47 |
114241102544455 has 32 divisors (see below), whose sum is σ = 140800458000384. Its totient is φ = 88941913564416.
The previous prime is 114241102544407. The next prime is 114241102544461. The reversal of 114241102544455 is 554445201142411.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 114241102544455 - 221 = 114241100447303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 38371944 + ... + 41241826.
It is an arithmetic number, because the mean of its divisors is an integer number (4400014312512).
Almost surely, 2114241102544455 is an apocalyptic number.
114241102544455 is a deficient number, since it is larger than the sum of its proper divisors (26559355455929).
114241102544455 is a wasteful number, since it uses less digits than its factorization.
114241102544455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2870895.
The product of its (nonzero) digits is 512000, while the sum is 43.
Adding to 114241102544455 its reverse (554445201142411), we get a palindrome (668686303686866).
The spelling of 114241102544455 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred two million, five hundred forty-four thousand, four hundred fifty-five".
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