Base | Representation |
---|---|
bin | 11001111110011011011010… |
… | …110011101110100101111111 |
3 | 112222111100112102112121012111 |
4 | 121332123122303232211333 |
5 | 104433212000022213122 |
6 | 1042545404325314451 |
7 | 33030440465362501 |
oct | 3176333263564577 |
9 | 488440472477174 |
10 | 114241211132287 |
11 | 33445475470678 |
12 | 10990866565a27 |
13 | 4b98b9135cb25 |
14 | 202d438719d71 |
15 | d31a21b12d77 |
hex | 67e6dacee97f |
114241211132287 has 2 divisors, whose sum is σ = 114241211132288. Its totient is φ = 114241211132286.
The previous prime is 114241211132263. The next prime is 114241211132329. The reversal of 114241211132287 is 782231112142411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114241211132287 - 231 = 114239063648639 is a prime.
It is a super-2 number, since 2×1142412111322872 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114241211135287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120605566143 + 57120605566144.
It is an arithmetic number, because the mean of its divisors is an integer number (57120605566144).
Almost surely, 2114241211132287 is an apocalyptic number.
114241211132287 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241211132287 is an equidigital number, since it uses as much as digits as its factorization.
114241211132287 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43008, while the sum is 40.
Adding to 114241211132287 its reverse (782231112142411), we get a palindrome (896472323274698).
The spelling of 114241211132287 in words is "one hundred fourteen trillion, two hundred forty-one billion, two hundred eleven million, one hundred thirty-two thousand, two hundred eighty-seven".
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