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11424121220023 is a prime number
BaseRepresentation
bin1010011000111110001010…
…1011111110101110110111
31111110010122122112222121121
42212033202223332232313
52444133100013020043
640144100245124411
72256236242110061
oct246174253765667
944403578488547
1011424121220023
113704a40669996
1213460a30b9707
1364b3a01c1a45
142b6d050ca731
1514c27aa3aded
hexa63e2afebb7

11424121220023 has 2 divisors, whose sum is σ = 11424121220024. Its totient is φ = 11424121220022.

The previous prime is 11424121219991. The next prime is 11424121220041. The reversal of 11424121220023 is 32002212142411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11424121220023 - 25 = 11424121219991 is a prime.

It is a super-2 number, since 2×114241212200232 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11424121220023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11424121220623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712060610011 + 5712060610012.

It is an arithmetic number, because the mean of its divisors is an integer number (5712060610012).

Almost surely, 211424121220023 is an apocalyptic number.

11424121220023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11424121220023 is an equidigital number, since it uses as much as digits as its factorization.

11424121220023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 11424121220023 its reverse (32002212142411), we get a palindrome (43426333362434).

The spelling of 11424121220023 in words is "eleven trillion, four hundred twenty-four billion, one hundred twenty-one million, two hundred twenty thousand, twenty-three".