Base | Representation |
---|---|
bin | 11001111110011100010001… |
… | …101010110100000011000011 |
3 | 112222111102220120110021020221 |
4 | 121332130101222310003003 |
5 | 104433220341133322321 |
6 | 1042550035525043511 |
7 | 33030502342625401 |
oct | 3176342152640303 |
9 | 488442816407227 |
10 | 114242131542211 |
11 | 334458a7a73232 |
12 | 10990a82856597 |
13 | 4b98ca9c5139a |
14 | 202d4c4a6a471 |
15 | d31a77821e41 |
hex | 67e711ab40c3 |
114242131542211 has 2 divisors, whose sum is σ = 114242131542212. Its totient is φ = 114242131542210.
The previous prime is 114242131542197. The next prime is 114242131542233. The reversal of 114242131542211 is 112245131242411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114242131542211 - 25 = 114242131542179 is a prime.
It is not a weakly prime, because it can be changed into another prime (114242131542811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121065771105 + 57121065771106.
It is an arithmetic number, because the mean of its divisors is an integer number (57121065771106).
Almost surely, 2114242131542211 is an apocalyptic number.
114242131542211 is a deficient number, since it is larger than the sum of its proper divisors (1).
114242131542211 is an equidigital number, since it uses as much as digits as its factorization.
114242131542211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15360, while the sum is 34.
Adding to 114242131542211 its reverse (112245131242411), we get a palindrome (226487262784622).
The spelling of 114242131542211 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-one million, five hundred forty-two thousand, two hundred eleven".
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