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114242131542233 is a prime number
BaseRepresentation
bin11001111110011100010001…
…101010110100000011011001
3112222111102220120110021021202
4121332130101222310003121
5104433220341133322413
61042550035525043545
733030502342625432
oct3176342152640331
9488442816407252
10114242131542233
11334458a7a73252
1210990a828565b5
134b98ca9c513b6
14202d4c4a6a489
15d31a77821e58
hex67e711ab40d9

114242131542233 has 2 divisors, whose sum is σ = 114242131542234. Its totient is φ = 114242131542232.

The previous prime is 114242131542211. The next prime is 114242131542289. The reversal of 114242131542233 is 332245131242411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97720085310409 + 16522046231824 = 9885347^2 + 4064732^2 .

It is an emirp because it is prime and its reverse (332245131242411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114242131542233 is a prime.

It is not a weakly prime, because it can be changed into another prime (114242131542533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121065771116 + 57121065771117.

It is an arithmetic number, because the mean of its divisors is an integer number (57121065771117).

Almost surely, 2114242131542233 is an apocalyptic number.

It is an amenable number.

114242131542233 is a deficient number, since it is larger than the sum of its proper divisors (1).

114242131542233 is an equidigital number, since it uses as much as digits as its factorization.

114242131542233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 138240, while the sum is 38.

Adding to 114242131542233 its reverse (332245131242411), we get a palindrome (446487262784644).

The spelling of 114242131542233 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-one million, five hundred forty-two thousand, two hundred thirty-three".