Base | Representation |
---|---|
bin | 10101010001111000… |
… | …10000010110000111 |
3 | 1002111011211200210202 |
4 | 22220330100112013 |
5 | 141344110134341 |
6 | 5125342241115 |
7 | 553050653201 |
oct | 125074202607 |
9 | 32434750722 |
10 | 11424302471 |
11 | 49327a259a |
12 | 2269b8619b |
13 | 1100ac77ba |
14 | 7a539d771 |
15 | 46ce5379b |
hex | 2a8f10587 |
11424302471 has 2 divisors, whose sum is σ = 11424302472. Its totient is φ = 11424302470.
The previous prime is 11424302441. The next prime is 11424302473. The reversal of 11424302471 is 17420342411.
It is a strong prime.
It is an emirp because it is prime and its reverse (17420342411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11424302471 - 214 = 11424286087 is a prime.
It is a super-3 number, since 3×114243024713 (a number of 31 digits) contains 333 as substring.
Together with 11424302473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11424302473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712151235 + 5712151236.
It is an arithmetic number, because the mean of its divisors is an integer number (5712151236).
Almost surely, 211424302471 is an apocalyptic number.
11424302471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424302471 is an equidigital number, since it uses as much as digits as its factorization.
11424302471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 29.
Adding to 11424302471 its reverse (17420342411), we get a palindrome (28844644882).
The spelling of 11424302471 in words is "eleven billion, four hundred twenty-four million, three hundred two thousand, four hundred seventy-one".
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