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1142505437 is a prime number
BaseRepresentation
bin100010000011001…
…0011111111011101
32221121211021211012
41010012103333131
54314440133222
6305211505005
740212064433
oct10406237735
92847737735
101142505437
11536a07277
1227a758165
13152913a28
14aba44d53
156a4801e2
hex44193fdd

1142505437 has 2 divisors, whose sum is σ = 1142505438. Its totient is φ = 1142505436.

The previous prime is 1142505421. The next prime is 1142505457. The reversal of 1142505437 is 7345052411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 995150116 + 147355321 = 31546^2 + 12139^2 .

It is an emirp because it is prime and its reverse (7345052411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1142505437 - 24 = 1142505421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1142505457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571252718 + 571252719.

It is an arithmetic number, because the mean of its divisors is an integer number (571252719).

Almost surely, 21142505437 is an apocalyptic number.

It is an amenable number.

1142505437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142505437 is an equidigital number, since it uses as much as digits as its factorization.

1142505437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 32.

The square root of 1142505437 is about 33800.9679890976. The cubic root of 1142505437 is about 1045.4086562081.

Adding to 1142505437 its reverse (7345052411), we get a palindrome (8487557848).

The spelling of 1142505437 in words is "one billion, one hundred forty-two million, five hundred five thousand, four hundred thirty-seven".