Base | Representation |
---|---|
bin | 110101001110011010… |
… | …1001101010010111011 |
3 | 101221000210021001121221 |
4 | 1222130311031102323 |
5 | 3333041341442413 |
6 | 124301525012511 |
7 | 11154316614004 |
oct | 1523465152273 |
9 | 357023231557 |
10 | 114300343483 |
11 | 44524622897 |
12 | 1a19ab54137 |
13 | aa17409851 |
14 | 576439a1ab |
15 | 2e8e8e868d |
hex | 1a9cd4d4bb |
114300343483 has 2 divisors, whose sum is σ = 114300343484. Its totient is φ = 114300343482.
The previous prime is 114300343481. The next prime is 114300343511. The reversal of 114300343483 is 384343003411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114300343483 - 21 = 114300343481 is a prime.
It is a super-3 number, since 3×1143003434833 (a number of 34 digits) contains 333 as substring.
Together with 114300343481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (114300343481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150171741 + 57150171742.
It is an arithmetic number, because the mean of its divisors is an integer number (57150171742).
Almost surely, 2114300343483 is an apocalyptic number.
114300343483 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300343483 is an equidigital number, since it uses as much as digits as its factorization.
114300343483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 114300343483 its reverse (384343003411), we get a palindrome (498643346894).
The spelling of 114300343483 in words is "one hundred fourteen billion, three hundred million, three hundred forty-three thousand, four hundred eighty-three".
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