Base | Representation |
---|---|
bin | 1010011001010101010011… |
… | …1001111010110111100011 |
3 | 1111110201200112001212021221 |
4 | 2212111110321322313203 |
5 | 2444233310101203011 |
6 | 40151004445155511 |
7 | 2256546202461136 |
oct | 246252471726743 |
9 | 44421615055257 |
10 | 11430332444131 |
11 | 3707638749557 |
12 | 134733725bb97 |
13 | 64bb4cc74893 |
14 | 2b7333da021d |
15 | 14c4e0e98971 |
hex | a6554e7ade3 |
11430332444131 has 2 divisors, whose sum is σ = 11430332444132. Its totient is φ = 11430332444130.
The previous prime is 11430332444129. The next prime is 11430332444177. The reversal of 11430332444131 is 13144423303411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11430332444131 - 21 = 11430332444129 is a prime.
It is a super-2 number, since 2×114303324441312 (a number of 27 digits) contains 22 as substring.
Together with 11430332444129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11430332444431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715166222065 + 5715166222066.
It is an arithmetic number, because the mean of its divisors is an integer number (5715166222066).
Almost surely, 211430332444131 is an apocalyptic number.
11430332444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11430332444131 is an equidigital number, since it uses as much as digits as its factorization.
11430332444131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 11430332444131 its reverse (13144423303411), we get a palindrome (24574755747542).
The spelling of 11430332444131 in words is "eleven trillion, four hundred thirty billion, three hundred thirty-two million, four hundred forty-four thousand, one hundred thirty-one".
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