Search a number
-
+
11431421413 is a prime number
BaseRepresentation
bin10101010010101110…
…11010010111100101
31002111200020101011021
422221113122113211
5141402420441123
65130155011141
7553165323136
oct125127322745
932450211137
1011431421413
114936815115
122270439ab1
13110241aba9
147a62d3c8d
1546d8acc5d
hex2a95da5e5

11431421413 has 2 divisors, whose sum is σ = 11431421414. Its totient is φ = 11431421412.

The previous prime is 11431421389. The next prime is 11431421431. The reversal of 11431421413 is 31412413411.

Together with next prime (11431421431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7838977444 + 3592443969 = 88538^2 + 59937^2 .

It is a cyclic number.

It is not a de Polignac number, because 11431421413 - 25 = 11431421381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11431461413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715710706 + 5715710707.

It is an arithmetic number, because the mean of its divisors is an integer number (5715710707).

Almost surely, 211431421413 is an apocalyptic number.

It is an amenable number.

11431421413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11431421413 is an equidigital number, since it uses as much as digits as its factorization.

11431421413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 11431421413 its reverse (31412413411), we get a palindrome (42843834824).

The spelling of 11431421413 in words is "eleven billion, four hundred thirty-one million, four hundred twenty-one thousand, four hundred thirteen".