Base | Representation |
---|---|
bin | 11001111111100000010001… |
… | …100011010010100010101111 |
3 | 112222202102100221022010112201 |
4 | 121333200101203102202233 |
5 | 104440414403331421444 |
6 | 1043043352511442331 |
7 | 33035665556453545 |
oct | 3177402143224257 |
9 | 488672327263481 |
10 | 114315144013999 |
11 | 33473864673a05 |
12 | 109a305a5263a7 |
13 | 4ba2b44528c06 |
14 | 2032c4d7b3d95 |
15 | d338ec63bdd4 |
hex | 67f8118d28af |
114315144013999 has 2 divisors, whose sum is σ = 114315144014000. Its totient is φ = 114315144013998.
The previous prime is 114315144013991. The next prime is 114315144014003. The reversal of 114315144013999 is 999310441513411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114315144013999 - 23 = 114315144013991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114315144013991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157572006999 + 57157572007000.
It is an arithmetic number, because the mean of its divisors is an integer number (57157572007000).
Almost surely, 2114315144013999 is an apocalyptic number.
114315144013999 is a deficient number, since it is larger than the sum of its proper divisors (1).
114315144013999 is an equidigital number, since it uses as much as digits as its factorization.
114315144013999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 55.
The spelling of 114315144013999 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, thirteen thousand, nine hundred ninety-nine".
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