Base | Representation |
---|---|
bin | 11001111111100000010001… |
… | …100011010010100010110011 |
3 | 112222202102100221022010112212 |
4 | 121333200101203102202303 |
5 | 104440414403331422003 |
6 | 1043043352511442335 |
7 | 33035665556453552 |
oct | 3177402143224263 |
9 | 488672327263485 |
10 | 114315144014003 |
11 | 33473864673a09 |
12 | 109a305a5263ab |
13 | 4ba2b44528c0a |
14 | 2032c4d7b3d99 |
15 | d338ec63bdd8 |
hex | 67f8118d28b3 |
114315144014003 has 2 divisors, whose sum is σ = 114315144014004. Its totient is φ = 114315144014002.
The previous prime is 114315144013999. The next prime is 114315144014021. The reversal of 114315144014003 is 300410441513411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114315144014003 - 22 = 114315144013999 is a prime.
It is not a weakly prime, because it can be changed into another prime (114315144014053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157572007001 + 57157572007002.
It is an arithmetic number, because the mean of its divisors is an integer number (57157572007002).
Almost surely, 2114315144014003 is an apocalyptic number.
114315144014003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114315144014003 is an equidigital number, since it uses as much as digits as its factorization.
114315144014003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 114315144014003 its reverse (300410441513411), we get a palindrome (414725585527414).
The spelling of 114315144014003 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, fourteen thousand, three".
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