Base | Representation |
---|---|
bin | 10000101000101100010… |
… | …001100101111111100111 |
3 | 11001021210212012222021111 |
4 | 100220230101211333213 |
5 | 122212240223012221 |
6 | 2233103011325451 |
7 | 145410443414554 |
oct | 20505421457747 |
9 | 4037725188244 |
10 | 1143204110311 |
11 | 400914a0a58a |
12 | 1656888b0887 |
13 | 83a5a9081a3 |
14 | 3d48d40da2b |
15 | 1eb0d8e8be1 |
hex | 10a2c465fe7 |
1143204110311 has 2 divisors, whose sum is σ = 1143204110312. Its totient is φ = 1143204110310.
The previous prime is 1143204110291. The next prime is 1143204110333. The reversal of 1143204110311 is 1130114023411.
It is an a-pointer prime, because the next prime (1143204110333) can be obtained adding 1143204110311 to its sum of digits (22).
It is a weak prime.
It is an emirp because it is prime and its reverse (1130114023411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1143204110311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1143204110381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571602055155 + 571602055156.
It is an arithmetic number, because the mean of its divisors is an integer number (571602055156).
Almost surely, 21143204110311 is an apocalyptic number.
1143204110311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143204110311 is an equidigital number, since it uses as much as digits as its factorization.
1143204110311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1143204110311 its reverse (1130114023411), we get a palindrome (2273318133722).
The spelling of 1143204110311 in words is "one trillion, one hundred forty-three billion, two hundred four million, one hundred ten thousand, three hundred eleven".
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