Base | Representation |
---|---|
bin | 11001111111100110101011… |
… | …000000000010010011011000 |
3 | 112222210002002200022200010121 |
4 | 121333212223000002103120 |
5 | 104441022440414243000 |
6 | 1043050450303123024 |
7 | 33036331031523424 |
oct | 3177465300022330 |
9 | 488702080280117 |
10 | 114322013431000 |
11 | 3347676a238641 |
12 | 109a4456ba3474 |
13 | 4ba369a770bbb |
14 | 2033301c5bb84 |
15 | d33ba075eb1a |
hex | 67f9ab0024d8 |
114322013431000 has 128 divisors (see below), whose sum is σ = 274072333691520. Its totient is φ = 44607916800000.
The previous prime is 114322013430953. The next prime is 114322013431033. The reversal of 114322013431000 is 134310223411.
It is a super-2 number, since 2×1143220134310002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 337301620 + ... + 337640380.
It is an arithmetic number, because the mean of its divisors is an integer number (2141190106965).
Almost surely, 2114322013431000 is an apocalyptic number.
114322013431000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 114322013431000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (137036166845760).
114322013431000 is an abundant number, since it is smaller than the sum of its proper divisors (159750320260520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114322013431000 is a wasteful number, since it uses less digits than its factorization.
114322013431000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 347054 (or 347040 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 114322013431000 its reverse (134310223411), we get a palindrome (114456323654411).
The spelling of 114322013431000 in words is "one hundred fourteen trillion, three hundred twenty-two billion, thirteen million, four hundred thirty-one thousand".
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