11433440129 has 2 divisors, whose sum is σ = 11433440130. Its totient is φ = 11433440128.

The previous prime is 11433440107. The next prime is 11433440131. The reversal of 11433440129 is 92104433411.

11433440129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6181104400 + 5252335729 = 78620^2 + 72473^2 .

It is a cyclic number.

It is not a de Polignac number, because 11433440129 - 2²⁸ = 11165004673 is a prime.

Together with 11433440131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11433440095 and 11433440104.

It is not a weakly prime, because it can be changed into another prime (11433440159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716720064 + 5716720065.

It is an arithmetic number, because the mean of its divisors is an integer number (5716720065).

Almost surely, 2^11433440129 is an apocalyptic number.

It is an amenable number.

11433440129 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433440129 is an equidigital number, since it uses as much as digits as its factorization.

11433440129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 11433440129 in words is "eleven billion, four hundred thirty-three million, four hundred forty thousand, one hundred twenty-nine".