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114404322013 is a prime number
BaseRepresentation
bin110101010001100000…
…1110110101011011101
3101221022000220201100121
41222203001312223131
53333300001301023
6124320121354541
711160021456262
oct1524301665335
9357260821317
10114404322013
1144578291463
121a209938a51
13aa32b141c7
145774105269
152e98ad6d5d
hex1aa3076add

114404322013 has 2 divisors, whose sum is σ = 114404322014. Its totient is φ = 114404322012.

The previous prime is 114404322001. The next prime is 114404322091. The reversal of 114404322013 is 310223404411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109586157444 + 4818164569 = 331038^2 + 69413^2 .

It is a cyclic number.

It is not a de Polignac number, because 114404322013 - 233 = 105814387421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114408322013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57202161006 + 57202161007.

It is an arithmetic number, because the mean of its divisors is an integer number (57202161007).

Almost surely, 2114404322013 is an apocalyptic number.

It is an amenable number.

114404322013 is a deficient number, since it is larger than the sum of its proper divisors (1).

114404322013 is an equidigital number, since it uses as much as digits as its factorization.

114404322013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 114404322013 its reverse (310223404411), we get a palindrome (424627726424).

The spelling of 114404322013 in words is "one hundred fourteen billion, four hundred four million, three hundred twenty-two thousand, thirteen".