1144043431 has 2 divisors, whose sum is σ = 1144043432. Its totient is φ = 1144043430.

The previous prime is 1144043413. The next prime is 1144043443. The reversal of 1144043431 is 1343404411.

Together with previous prime (1144043413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1144043431 - 2²⁵ = 1110488999 is a prime.

It is a super-2 number, since 2×1144043431² = 2617670744028503522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1144043396 and 1144043405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1144043491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572021715 + 572021716.

It is an arithmetic number, because the mean of its divisors is an integer number (572021716).

Almost surely, 2^1144043431 is an apocalyptic number.

1144043431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144043431 is an equidigital number, since it uses as much as digits as its factorization.

1144043431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1144043431 is about 33823.7110766988. The cubic root of 1144043431 is about 1045.8775413040.

Adding to 1144043431 its reverse (1343404411), we get a palindrome (2487447842).

The spelling of 1144043431 in words is "one billion, one hundred forty-four million, forty-three thousand, four hundred thirty-one".