Base | Representation |
---|---|
bin | 10101010011111001… |
… | …00010010000011010 |
3 | 1002112100112210110021 |
4 | 22221330202100122 |
5 | 141412413344200 |
6 | 5131143341054 |
7 | 553344124225 |
oct | 125174422032 |
9 | 32470483407 |
10 | 11441153050 |
11 | 4941261698 |
12 | 227375178a |
13 | 1104447562 |
14 | 7a77085bc |
15 | 46e68141a |
hex | 2a9f2241a |
11441153050 has 48 divisors (see below), whose sum is σ = 22413520800. Its totient is φ = 4333089600.
The previous prime is 11441153047. The next prime is 11441153057. The reversal of 11441153050 is 5035114411.
It is a super-2 number, since 2×114411530502 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (11441153057) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3058081 + ... + 3061819.
It is an arithmetic number, because the mean of its divisors is an integer number (466948350).
Almost surely, 211441153050 is an apocalyptic number.
11441153050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11441153050 is a deficient number, since it is larger than the sum of its proper divisors (10972367750).
11441153050 is a wasteful number, since it uses less digits than its factorization.
11441153050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6991 (or 6986 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11441153050 its reverse (5035114411), we get a palindrome (16476267461).
The spelling of 11441153050 in words is "eleven billion, four hundred forty-one million, one hundred fifty-three thousand, fifty".
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