Base | Representation |
---|---|
bin | 1010011010000101011001… |
… | …0101010110001011110100 |
3 | 1111111222000011101100100210 |
4 | 2212201112111112023310 |
5 | 2444441224234004022 |
6 | 40200541423105420 |
7 | 2260514121162315 |
oct | 246412625261364 |
9 | 44458004340323 |
10 | 11443241313012 |
11 | 371206243a833 |
12 | 134993a442270 |
13 | 6501294b9832 |
14 | 2b7bda5a660c |
15 | 14c9e93e8a0c |
hex | a68565562f4 |
11443241313012 has 12 divisors (see below), whose sum is σ = 26700896397056. Its totient is φ = 3814413771000.
The previous prime is 11443241312981. The next prime is 11443241313017. The reversal of 11443241313012 is 21031314234411.
It is a tau number, because it is divible by the number of its divisors (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11443241313017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 476801721364 + ... + 476801721387.
Almost surely, 211443241313012 is an apocalyptic number.
11443241313012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11443241313012 is an abundant number, since it is smaller than the sum of its proper divisors (15257655084044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11443241313012 is a wasteful number, since it uses less digits than its factorization.
11443241313012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 953603442758 (or 953603442756 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 11443241313012 its reverse (21031314234411), we get a palindrome (32474555547423).
The spelling of 11443241313012 in words is "eleven trillion, four hundred forty-three billion, two hundred forty-one million, three hundred thirteen thousand, twelve".
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