Base | Representation |
---|---|
bin | 1010011010001000010000… |
… | …1110010001010111110111 |
3 | 1111112000222211002011210121 |
4 | 2212202010032101113313 |
5 | 2444444313332211411 |
6 | 40201150044432411 |
7 | 2260542160201525 |
oct | 246420416212767 |
9 | 44460884064717 |
10 | 11444011210231 |
11 | 3712417a8aa26 |
12 | 1349b14248707 |
13 | 65021cb5ca12 |
14 | 2b7c70937315 |
15 | 14ca41cc6571 |
hex | a68843915f7 |
11444011210231 has 2 divisors, whose sum is σ = 11444011210232. Its totient is φ = 11444011210230.
The previous prime is 11444011210201. The next prime is 11444011210277. The reversal of 11444011210231 is 13201211044411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11444011210231 - 215 = 11444011177463 is a prime.
It is a super-2 number, since 2×114440112102312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11444011210196 and 11444011210205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11444011210201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722005605115 + 5722005605116.
It is an arithmetic number, because the mean of its divisors is an integer number (5722005605116).
Almost surely, 211444011210231 is an apocalyptic number.
11444011210231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11444011210231 is an equidigital number, since it uses as much as digits as its factorization.
11444011210231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 11444011210231 its reverse (13201211044411), we get a palindrome (24645222254642).
The spelling of 11444011210231 in words is "eleven trillion, four hundred forty-four billion, eleven million, two hundred ten thousand, two hundred thirty-one".
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