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114441313157 is a prime number
BaseRepresentation
bin110101010010100111…
…0111101101110000101
3101221101121112001122222
41222211032331232011
53333333434010112
6124323522302125
711160651053213
oct1524516755605
9357347461588
10114441313157
1144597157456
121a21a1b7945
13aa3a696362
145778db3cb3
152e9be92372
hex1aa53bdb85

114441313157 has 2 divisors, whose sum is σ = 114441313158. Its totient is φ = 114441313156.

The previous prime is 114441313121. The next prime is 114441313159. The reversal of 114441313157 is 751313144411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91643031076 + 22798282081 = 302726^2 + 150991^2 .

It is an emirp because it is prime and its reverse (751313144411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114441313157 - 26 = 114441313093 is a prime.

Together with 114441313159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114441313159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57220656578 + 57220656579.

It is an arithmetic number, because the mean of its divisors is an integer number (57220656579).

Almost surely, 2114441313157 is an apocalyptic number.

It is an amenable number.

114441313157 is a deficient number, since it is larger than the sum of its proper divisors (1).

114441313157 is an equidigital number, since it uses as much as digits as its factorization.

114441313157 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 35.

Adding to 114441313157 its reverse (751313144411), we get a palindrome (865754457568).

The spelling of 114441313157 in words is "one hundred fourteen billion, four hundred forty-one million, three hundred thirteen thousand, one hundred fifty-seven".