114442020131 has 2 divisors, whose sum is σ = 114442020132. Its totient is φ = 114442020130.

The previous prime is 114442020113. The next prime is 114442020149. The reversal of 114442020131 is 131020244411.

Together with previous prime (114442020113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (114442020113) and next prime (114442020149).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114442020131 is a prime.

It is a super-2 number, since 2×114442020131² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 114442020097 and 114442020106.

It is not a weakly prime, because it can be changed into another prime (114442020331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57221010065 + 57221010066.

It is an arithmetic number, because the mean of its divisors is an integer number (57221010066).

Almost surely, 2^114442020131 is an apocalyptic number.

114442020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

114442020131 is an equidigital number, since it uses as much as digits as its factorization.

114442020131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 114442020131 its reverse (131020244411), we get a palindrome (245462264542).

The spelling of 114442020131 in words is "one hundred fourteen billion, four hundred forty-two million, twenty thousand, one hundred thirty-one".