Base | Representation |
---|---|
bin | 110101010011000001… |
… | …1111100110110000111 |
3 | 101221102120122202020021 |
4 | 1222212003330312013 |
5 | 3333401013000312 |
6 | 124325140120011 |
7 | 11161210114042 |
oct | 1524603746607 |
9 | 357376582207 |
10 | 114455203207 |
11 | 445a3a84234 |
12 | 1a222996007 |
13 | aa4051a717 |
14 | 577ab8bc59 |
15 | 2e9d2d7c07 |
hex | 1aa60fcd87 |
114455203207 has 2 divisors, whose sum is σ = 114455203208. Its totient is φ = 114455203206.
The previous prime is 114455203193. The next prime is 114455203211. The reversal of 114455203207 is 702302554411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114455203207 is a prime.
It is a super-3 number, since 3×1144552032073 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114455203237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57227601603 + 57227601604.
It is an arithmetic number, because the mean of its divisors is an integer number (57227601604).
Almost surely, 2114455203207 is an apocalyptic number.
114455203207 is a deficient number, since it is larger than the sum of its proper divisors (1).
114455203207 is an equidigital number, since it uses as much as digits as its factorization.
114455203207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 34.
Adding to 114455203207 its reverse (702302554411), we get a palindrome (816757757618).
The spelling of 114455203207 in words is "one hundred fourteen billion, four hundred fifty-five million, two hundred three thousand, two hundred seven".
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