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11449075247 is a prime number
BaseRepresentation
bin10101010100110101…
…10000011000101111
31002112220110021122222
422222122300120233
5141421430401442
65132025225555
7553501351061
oct125232603057
932486407588
1011449075247
114945782765
1222763322bb
131105c8c44c
147a87ab731
154701e88d2
hex2aa6b062f

11449075247 has 2 divisors, whose sum is σ = 11449075248. Its totient is φ = 11449075246.

The previous prime is 11449075223. The next prime is 11449075249. The reversal of 11449075247 is 74257094411.

11449075247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11449075247 - 220 = 11448026671 is a prime.

It is a super-2 number, since 2×114490752472 (a number of 21 digits) contains 22 as substring.

Together with 11449075249, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11449075198 and 11449075207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11449075249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5724537623 + 5724537624.

It is an arithmetic number, because the mean of its divisors is an integer number (5724537624).

Almost surely, 211449075247 is an apocalyptic number.

11449075247 is a deficient number, since it is larger than the sum of its proper divisors (1).

11449075247 is an equidigital number, since it uses as much as digits as its factorization.

11449075247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 44.

The spelling of 11449075247 in words is "eleven billion, four hundred forty-nine million, seventy-five thousand, two hundred forty-seven".