114511202404213 has 2 divisors, whose sum is σ = 114511202404214. Its totient is φ = 114511202404212.

The previous prime is 114511202404211. The next prime is 114511202404231. The reversal of 114511202404213 is 312404202115411.

Together with next prime (114511202404231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108263567180484 + 6247635223729 = 10404978^2 + 2499527^2 .

It is a cyclic number.

It is not a de Polignac number, because 114511202404213 - 2¹ = 114511202404211 is a prime.

It is a super-2 number, since 2×114511202404213² (a number of 29 digits) contains 22 as substring.

Together with 114511202404211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114511202404211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255601202106 + 57255601202107.

It is an arithmetic number, because the mean of its divisors is an integer number (57255601202107).

Almost surely, 2^{114511202404213} is an apocalyptic number.

It is an amenable number.

114511202404213 is a deficient number, since it is larger than the sum of its proper divisors (1).

114511202404213 is an equidigital number, since it uses as much as digits as its factorization.

114511202404213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 114511202404213 its reverse (312404202115411), we get a palindrome (426915404519624).

The spelling of 114511202404213 in words is "one hundred fourteen trillion, five hundred eleven billion, two hundred two million, four hundred four thousand, two hundred thirteen".