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11451635406311 is a prime number
BaseRepresentation
bin1010011010100100101010…
…1010010001010111100111
31111112202200011100110122012
42212221022222101113213
53000110422131000221
640204450401424435
72261232125613452
oct246511252212747
944482604313565
1011451635406311
11371567a709321
12134b4a163b11b
13650b66583849
142b8395338499
1514cd3b2dc65b
hexa6a4aa915e7

11451635406311 has 2 divisors, whose sum is σ = 11451635406312. Its totient is φ = 11451635406310.

The previous prime is 11451635406307. The next prime is 11451635406313. The reversal of 11451635406311 is 11360453615411.

11451635406311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11451635406311 - 22 = 11451635406307 is a prime.

It is a super-2 number, since 2×114516354063112 (a number of 27 digits) contains 22 as substring.

Together with 11451635406313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11451635406313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725817703155 + 5725817703156.

It is an arithmetic number, because the mean of its divisors is an integer number (5725817703156).

Almost surely, 211451635406311 is an apocalyptic number.

11451635406311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11451635406311 is an equidigital number, since it uses as much as digits as its factorization.

11451635406311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 11451635406311 in words is "eleven trillion, four hundred fifty-one billion, six hundred thirty-five million, four hundred six thousand, three hundred eleven".