Search a number
-
+
114531251551309 is a prime number
BaseRepresentation
bin11010000010101001100010…
…100100000111110001001101
3120000112002011211202111022001
4122002221202210013301031
5110002440000344120214
61043330533002152301
733060416116304665
oct3202514244076115
9500462154674261
10114531251551309
113354748174a30a
1210a18b104b2691
134bba334983748
14203d4b0c1b1a5
15d39349c49c74
hex682a62907c4d

114531251551309 has 2 divisors, whose sum is σ = 114531251551310. Its totient is φ = 114531251551308.

The previous prime is 114531251551307. The next prime is 114531251551363. The reversal of 114531251551309 is 903155152135411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113062496617225 + 1468754934084 = 10633085^2 + 1211922^2 .

It is a cyclic number.

It is not a de Polignac number, because 114531251551309 - 21 = 114531251551307 is a prime.

It is a super-2 number, since 2×1145312515513092 (a number of 29 digits) contains 22 as substring.

Together with 114531251551307, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114531251551307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57265625775654 + 57265625775655.

It is an arithmetic number, because the mean of its divisors is an integer number (57265625775655).

Almost surely, 2114531251551309 is an apocalyptic number.

It is an amenable number.

114531251551309 is a deficient number, since it is larger than the sum of its proper divisors (1).

114531251551309 is an equidigital number, since it uses as much as digits as its factorization.

114531251551309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405000, while the sum is 46.

The spelling of 114531251551309 in words is "one hundred fourteen trillion, five hundred thirty-one billion, two hundred fifty-one million, five hundred fifty-one thousand, three hundred nine".