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11454214181 is a prime number
BaseRepresentation
bin10101010101011100…
…10111000000100101
31002120021010100221212
422222232113000211
5141424234323211
65132331321205
7553563133304
oct125256270045
932507110855
1011454214181
114948672713
122277bb0205
13110706b537
147a934843b
154708b138b
hex2aab97025

11454214181 has 2 divisors, whose sum is σ = 11454214182. Its totient is φ = 11454214180.

The previous prime is 11454214099. The next prime is 11454214267. The reversal of 11454214181 is 18141245411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10986184225 + 468029956 = 104815^2 + 21634^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11454214181 is a prime.

It is a super-2 number, since 2×114542141812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11454214081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5727107090 + 5727107091.

It is an arithmetic number, because the mean of its divisors is an integer number (5727107091).

Almost surely, 211454214181 is an apocalyptic number.

It is an amenable number.

11454214181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11454214181 is an equidigital number, since it uses as much as digits as its factorization.

11454214181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5120, while the sum is 32.

Adding to 11454214181 its reverse (18141245411), we get a palindrome (29595459592).

The spelling of 11454214181 in words is "eleven billion, four hundred fifty-four million, two hundred fourteen thousand, one hundred eighty-one".