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114548265281 is a prime number
BaseRepresentation
bin110101010101110011…
…0111101000101000001
3101221200001202210101202
41222223212331011001
53334043323442111
6124342302510545
711163420122042
oct1525346750501
9357601683352
10114548265281
114464156713a
121a249b95455
13aa568a2338
1457892948c9
152ea656bb3b
hex1aab9bd141

114548265281 has 2 divisors, whose sum is σ = 114548265282. Its totient is φ = 114548265280.

The previous prime is 114548265259. The next prime is 114548265283. The reversal of 114548265281 is 182562845411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113512391056 + 1035874225 = 336916^2 + 32185^2 .

It is an emirp because it is prime and its reverse (182562845411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114548265281 - 226 = 114481156417 is a prime.

It is a super-2 number, since 2×1145482652812 (a number of 23 digits) contains 22 as substring.

Together with 114548265283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114548265283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57274132640 + 57274132641.

It is an arithmetic number, because the mean of its divisors is an integer number (57274132641).

Almost surely, 2114548265281 is an apocalyptic number.

It is an amenable number.

114548265281 is a deficient number, since it is larger than the sum of its proper divisors (1).

114548265281 is an equidigital number, since it uses as much as digits as its factorization.

114548265281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 614400, while the sum is 47.

The spelling of 114548265281 in words is "one hundred fourteen billion, five hundred forty-eight million, two hundred sixty-five thousand, two hundred eighty-one".