Base | Representation |
---|---|
bin | 1010011010110010000001… |
… | …0101010000110101000100 |
3 | 1111120002220222211001001210 |
4 | 2212230200111100311010 |
5 | 3000140242334121200 |
6 | 40210242220451420 |
7 | 2261420015221110 |
oct | 246544025206504 |
9 | 44502828731053 |
10 | 11455220223300 |
11 | 371714a1a7397 |
12 | 13501220a9b70 |
13 | 6512b8178c29 |
14 | 2b8615494740 |
15 | 14ce9ada0650 |
hex | a6b20550d44 |
11455220223300 has 72 divisors (see below), whose sum is σ = 37878594878656. Its totient is φ = 2618336050560.
The previous prime is 11455220223229. The next prime is 11455220223331. The reversal of 11455220223300 is 332202255411.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2727431287 + ... + 2727435486.
Almost surely, 211455220223300 is an apocalyptic number.
11455220223300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11455220223300 is an abundant number, since it is smaller than the sum of its proper divisors (26423374655356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11455220223300 is a wasteful number, since it uses less digits than its factorization.
11455220223300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5454866797 (or 5454866790 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 11455220223300 its reverse (332202255411), we get a palindrome (11787422478711).
The spelling of 11455220223300 in words is "eleven trillion, four hundred fifty-five billion, two hundred twenty million, two hundred twenty-three thousand, three hundred".
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