Base | Representation |
---|---|
bin | 10000101101011101111… |
… | …000010010111100101101 |
3 | 11001210001011221112121122 |
4 | 100231131320102330231 |
5 | 122303240303304142 |
6 | 2235311445110325 |
7 | 145651502025353 |
oct | 20553570227455 |
9 | 4053034845548 |
10 | 1148331306797 |
11 | 4030060a4154 |
12 | 1666799b83a5 |
13 | 84396c1046c |
14 | 3d8183417d3 |
15 | 1ed0dac81d2 |
hex | 10b5de12f2d |
1148331306797 has 2 divisors, whose sum is σ = 1148331306798. Its totient is φ = 1148331306796.
The previous prime is 1148331306781. The next prime is 1148331306869. The reversal of 1148331306797 is 7976031338411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1138444186441 + 9887120356 = 1066979^2 + 99434^2 .
It is a cyclic number.
It is not a de Polignac number, because 1148331306797 - 24 = 1148331306781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1148334306797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574165653398 + 574165653399.
It is an arithmetic number, because the mean of its divisors is an integer number (574165653399).
Almost surely, 21148331306797 is an apocalyptic number.
It is an amenable number.
1148331306797 is a deficient number, since it is larger than the sum of its proper divisors (1).
1148331306797 is an equidigital number, since it uses as much as digits as its factorization.
1148331306797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2286144, while the sum is 53.
The spelling of 1148331306797 in words is "one trillion, one hundred forty-eight billion, three hundred thirty-one million, three hundred six thousand, seven hundred ninety-seven".
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