Base | Representation |
---|---|
bin | 10101011001111001… |
… | …00111001111011101 |
3 | 1002122212021221111122 |
4 | 22230330213033131 |
5 | 142013311130432 |
6 | 5140142500325 |
7 | 554525116241 |
oct | 125474471735 |
9 | 32585257448 |
10 | 11491505117 |
11 | 4967722974 |
12 | 22885946a5 |
13 | 11119c6c91 |
14 | 7b0294421 |
15 | 473cca612 |
hex | 2acf273dd |
11491505117 has 2 divisors, whose sum is σ = 11491505118. Its totient is φ = 11491505116.
The previous prime is 11491505093. The next prime is 11491505119. The reversal of 11491505117 is 71150519411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8814580996 + 2676924121 = 93886^2 + 51739^2 .
It is a cyclic number.
It is not a de Polignac number, because 11491505117 - 216 = 11491439581 is a prime.
Together with 11491505119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11491505119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5745752558 + 5745752559.
It is an arithmetic number, because the mean of its divisors is an integer number (5745752559).
Almost surely, 211491505117 is an apocalyptic number.
It is an amenable number.
11491505117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11491505117 is an equidigital number, since it uses as much as digits as its factorization.
11491505117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 35.
The spelling of 11491505117 in words is "eleven billion, four hundred ninety-one million, five hundred five thousand, one hundred seventeen".
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